100341114131 has 2 divisors, whose sum is σ = 100341114132. Its totient is φ = 100341114130.

The previous prime is 100341114031. The next prime is 100341114173. The reversal of 100341114131 is 131411143001.

It is a strong prime.

It is an emirp because it is prime and its reverse (131411143001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100341114131 - 2²⁶ = 100274005267 is a prime.

It is a super-2 number, since 2×100341114131² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (100341114031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50170557065 + 50170557066.

It is an arithmetic number, because the mean of its divisors is an integer number (50170557066).

Almost surely, 2^100341114131 is an apocalyptic number.

100341114131 is a deficient number, since it is larger than the sum of its proper divisors (1).

100341114131 is an equidigital number, since it uses as much as digits as its factorization.

100341114131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 100341114131 its reverse (131411143001), we get a palindrome (231752257132).

The spelling of 100341114131 in words is "one hundred billion, three hundred forty-one million, one hundred fourteen thousand, one hundred thirty-one".