Base | Representation |
---|---|
bin | 1001001000000100011010… |
… | …1111011001010011110011 |
3 | 1022112021002202211102022121 |
4 | 2102001012233121103303 |
5 | 2303400100442324021 |
6 | 33201354542015111 |
7 | 2053643404255141 |
oct | 222010657312363 |
9 | 38467082742277 |
10 | 10034230433011 |
11 | 321954753aa84 |
12 | 116084b577497 |
13 | 57a2baac3405 |
14 | 269933352591 |
15 | 12603015d741 |
hex | 92046bd94f3 |
10034230433011 has 4 divisors (see below), whose sum is σ = 10085165613072. Its totient is φ = 9983295252952.
The previous prime is 10034230432997. The next prime is 10034230433081. The reversal of 10034230433011 is 11033403243001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10034230433011 - 27 = 10034230432883 is a prime.
It is a super-2 number, since 2×100342304330112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10034230433081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25467589735 + ... + 25467590128.
It is an arithmetic number, because the mean of its divisors is an integer number (2521291403268).
Almost surely, 210034230433011 is an apocalyptic number.
10034230433011 is a deficient number, since it is larger than the sum of its proper divisors (50935180061).
10034230433011 is an equidigital number, since it uses as much as digits as its factorization.
10034230433011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50935180060.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 10034230433011 its reverse (11033403243001), we get a palindrome (21067633676012).
The spelling of 10034230433011 in words is "ten trillion, thirty-four billion, two hundred thirty million, four hundred thirty-three thousand, eleven".
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