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10035425141051 is a prime number
BaseRepresentation
bin1001001000001000110111…
…1100110110000100111011
31022112101012000212212122112
42102002031330312010323
52303410022314003201
633202113300442535
72054015122153022
oct222021574660473
938471160785575
1010035425141051
113219aaa9618a2
121160b236a944b
1357a44b483c4b
14269a07ca58b9
1512609eea10bb
hex9208df3613b

10035425141051 has 2 divisors, whose sum is σ = 10035425141052. Its totient is φ = 10035425141050.

The previous prime is 10035425141009. The next prime is 10035425141059. The reversal of 10035425141051 is 15014152453001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10035425141051 - 238 = 9760547234107 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10035425140999 and 10035425141017.

It is not a weakly prime, because it can be changed into another prime (10035425141059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5017712570525 + 5017712570526.

It is an arithmetic number, because the mean of its divisors is an integer number (5017712570526).

Almost surely, 210035425141051 is an apocalyptic number.

10035425141051 is a deficient number, since it is larger than the sum of its proper divisors (1).

10035425141051 is an equidigital number, since it uses as much as digits as its factorization.

10035425141051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 10035425141051 its reverse (15014152453001), we get a palindrome (25049577594052).

The spelling of 10035425141051 in words is "ten trillion, thirty-five billion, four hundred twenty-five million, one hundred forty-one thousand, fifty-one".