Base | Representation |
---|---|
bin | 1001001000001000110111… |
… | …1100110110000100111011 |
3 | 1022112101012000212212122112 |
4 | 2102002031330312010323 |
5 | 2303410022314003201 |
6 | 33202113300442535 |
7 | 2054015122153022 |
oct | 222021574660473 |
9 | 38471160785575 |
10 | 10035425141051 |
11 | 3219aaa9618a2 |
12 | 1160b236a944b |
13 | 57a44b483c4b |
14 | 269a07ca58b9 |
15 | 12609eea10bb |
hex | 9208df3613b |
10035425141051 has 2 divisors, whose sum is σ = 10035425141052. Its totient is φ = 10035425141050.
The previous prime is 10035425141009. The next prime is 10035425141059. The reversal of 10035425141051 is 15014152453001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10035425141051 - 238 = 9760547234107 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10035425140999 and 10035425141017.
It is not a weakly prime, because it can be changed into another prime (10035425141059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5017712570525 + 5017712570526.
It is an arithmetic number, because the mean of its divisors is an integer number (5017712570526).
Almost surely, 210035425141051 is an apocalyptic number.
10035425141051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10035425141051 is an equidigital number, since it uses as much as digits as its factorization.
10035425141051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 10035425141051 its reverse (15014152453001), we get a palindrome (25049577594052).
The spelling of 10035425141051 in words is "ten trillion, thirty-five billion, four hundred twenty-five million, one hundred forty-one thousand, fifty-one".
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