Base | Representation |
---|---|
bin | 1001001000001001010011… |
… | …1011111011100101111011 |
3 | 1022112101111012102022010211 |
4 | 2102002110323323211323 |
5 | 2303410242314421021 |
6 | 33202133044451551 |
7 | 2054021044305544 |
oct | 222022473734573 |
9 | 38471435368124 |
10 | 10035542342011 |
11 | 321a06003169a |
12 | 1160b569a9bb7 |
13 | 57a46983ab24 |
14 | 269a196934cb |
15 | 1260aa4023e1 |
hex | 92094efb97b |
10035542342011 has 2 divisors, whose sum is σ = 10035542342012. Its totient is φ = 10035542342010.
The previous prime is 10035542341939. The next prime is 10035542342051. The reversal of 10035542342011 is 11024324553001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10035542342011 - 227 = 10035408124283 is a prime.
It is a super-2 number, since 2×100355423420112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10035542342051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5017771171005 + 5017771171006.
It is an arithmetic number, because the mean of its divisors is an integer number (5017771171006).
Almost surely, 210035542342011 is an apocalyptic number.
10035542342011 is a deficient number, since it is larger than the sum of its proper divisors (1).
10035542342011 is an equidigital number, since it uses as much as digits as its factorization.
10035542342011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 10035542342011 its reverse (11024324553001), we get a palindrome (21059866895012).
The spelling of 10035542342011 in words is "ten trillion, thirty-five billion, five hundred forty-two million, three hundred forty-two thousand, eleven".
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