Base | Representation |
---|---|
bin | 1001001000011010000010… |
… | …0111001100110010101011 |
3 | 1022112211002011202120222111 |
4 | 2102012200213030302223 |
5 | 2303443441444420243 |
6 | 33204154431303151 |
7 | 2054240245056046 |
oct | 222064047146253 |
9 | 38484064676874 |
10 | 10040033201323 |
11 | 3220a54aa9774 |
12 | 11619aa97aab7 |
13 | 57aa04063c28 |
14 | 269d23c9dc5d |
15 | 12626e7d739d |
hex | 921a09cccab |
10040033201323 has 2 divisors, whose sum is σ = 10040033201324. Its totient is φ = 10040033201322.
The previous prime is 10040033201279. The next prime is 10040033201339. The reversal of 10040033201323 is 32310233004001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10040033201323 - 229 = 10039496330411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10040033201294 and 10040033201303.
It is not a weakly prime, because it can be changed into another prime (10040033201923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020016600661 + 5020016600662.
It is an arithmetic number, because the mean of its divisors is an integer number (5020016600662).
Almost surely, 210040033201323 is an apocalyptic number.
10040033201323 is a deficient number, since it is larger than the sum of its proper divisors (1).
10040033201323 is an equidigital number, since it uses as much as digits as its factorization.
10040033201323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 10040033201323 its reverse (32310233004001), we get a palindrome (42350266205324).
The spelling of 10040033201323 in words is "ten trillion, forty billion, thirty-three million, two hundred one thousand, three hundred twenty-three".
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