100401043331 has 2 divisors, whose sum is σ = 100401043332. Its totient is φ = 100401043330.

The previous prime is 100401043313. The next prime is 100401043339. The reversal of 100401043331 is 133340104001.

Together with previous prime (100401043313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100401043331 is a prime.

It is a super-2 number, since 2×100401043331² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (100401043339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50200521665 + 50200521666.

It is an arithmetic number, because the mean of its divisors is an integer number (50200521666).

Almost surely, 2^100401043331 is an apocalyptic number.

100401043331 is a deficient number, since it is larger than the sum of its proper divisors (1).

100401043331 is an equidigital number, since it uses as much as digits as its factorization.

100401043331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 100401043331 its reverse (133340104001), we get a palindrome (233741147332).

The spelling of 100401043331 in words is "one hundred billion, four hundred one million, forty-three thousand, three hundred thirty-one".