1004013113 has 4 divisors (see below), whose sum is σ = 1004078208. Its totient is φ = 1003948020.

The previous prime is 1004013103. The next prime is 1004013119. The reversal of 1004013113 is 3113104001.

1004013113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1004013113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1004013119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5120 + ... + 45102.

It is an arithmetic number, because the mean of its divisors is an integer number (251019552).

Almost surely, 2^1004013113 is an apocalyptic number.

It is an amenable number.

1004013113 is a deficient number, since it is larger than the sum of its proper divisors (65095).

1004013113 is an equidigital number, since it uses as much as digits as its factorization.

1004013113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65094.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 1004013113 is about 31686.1659561393. The cubic root of 1004013113 is about 1001.3359188594.

Adding to 1004013113 its reverse (3113104001), we get a palindrome (4117117114).

The spelling of 1004013113 in words is "one billion, four million, thirteen thousand, one hundred thirteen".