Base | Representation |
---|---|
bin | 11101001110001000101… |
… | …01110101111000000011 |
3 | 10112222112222110202002101 |
4 | 32213010111311320003 |
5 | 112422213442040003 |
6 | 2045124023531231 |
7 | 132352405266631 |
oct | 16470425657003 |
9 | 3488488422071 |
10 | 1004021440003 |
11 | 357891a2332a |
12 | 1427048b9b17 |
13 | 738a9485c3a |
14 | 3684857c351 |
15 | 1b1b482411d |
hex | e9c4575e03 |
1004021440003 has 2 divisors, whose sum is σ = 1004021440004. Its totient is φ = 1004021440002.
The previous prime is 1004021439937. The next prime is 1004021440007. The reversal of 1004021440003 is 3000441204001.
1004021440003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (3000441204001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1004021440003 - 213 = 1004021431811 is a prime.
It is not a weakly prime, because it can be changed into another prime (1004021440007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502010720001 + 502010720002.
It is an arithmetic number, because the mean of its divisors is an integer number (502010720002).
Almost surely, 21004021440003 is an apocalyptic number.
1004021440003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004021440003 is an equidigital number, since it uses as much as digits as its factorization.
1004021440003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 1004021440003 its reverse (3000441204001), we get a palindrome (4004462644004).
The spelling of 1004021440003 in words is "one trillion, four billion, twenty-one million, four hundred forty thousand, three".
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