100402825489233 has 4 divisors (see below), whose sum is σ = 133870433985648. Its totient is φ = 66935216992820.

The previous prime is 100402825489231. The next prime is 100402825489237. The reversal of 100402825489233 is 332984528204001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100402825489233 - 2¹ = 100402825489231 is a prime.

It is not an unprimeable number, because it can be changed into a prime (100402825489231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16733804248203 + ... + 16733804248208.

It is an arithmetic number, because the mean of its divisors is an integer number (33467608496412).

Almost surely, 2^{100402825489233} is an apocalyptic number.

It is an amenable number.

100402825489233 is a deficient number, since it is larger than the sum of its proper divisors (33467608496415).

100402825489233 is an equidigital number, since it uses as much as digits as its factorization.

100402825489233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33467608496414.

The product of its (nonzero) digits is 3317760, while the sum is 51.

The spelling of 100402825489233 in words is "one hundred trillion, four hundred two billion, eight hundred twenty-five million, four hundred eighty-nine thousand, two hundred thirty-three".