10040312017 has 2 divisors, whose sum is σ = 10040312018. Its totient is φ = 10040312016.

The previous prime is 10040311999. The next prime is 10040312021. The reversal of 10040312017 is 71021304001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7500252816 + 2540059201 = 86604^2 + 50399^2 .

It is an emirp because it is prime and its reverse (71021304001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10040312017 is a prime.

It is a super-3 number, since 3×10040312017³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10040311985 and 10040312003.

It is not a weakly prime, because it can be changed into another prime (10040312027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020156008 + 5020156009.

It is an arithmetic number, because the mean of its divisors is an integer number (5020156009).

Almost surely, 2^10040312017 is an apocalyptic number.

It is an amenable number.

10040312017 is a deficient number, since it is larger than the sum of its proper divisors (1).

10040312017 is an equidigital number, since it uses as much as digits as its factorization.

10040312017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 19.

Adding to 10040312017 its reverse (71021304001), we get a palindrome (81061616018).

The spelling of 10040312017 in words is "ten billion, forty million, three hundred twelve thousand, seventeen".