10040357113 has 2 divisors, whose sum is σ = 10040357114. Its totient is φ = 10040357112.

The previous prime is 10040357101. The next prime is 10040357123. The reversal of 10040357113 is 31175304001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5338786489 + 4701570624 = 73067^2 + 68568^2 .

It is an emirp because it is prime and its reverse (31175304001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10040357113 is a prime.

It is not a weakly prime, because it can be changed into another prime (10040357123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020178556 + 5020178557.

It is an arithmetic number, because the mean of its divisors is an integer number (5020178557).

Almost surely, 2^10040357113 is an apocalyptic number.

It is an amenable number.

10040357113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10040357113 is an equidigital number, since it uses as much as digits as its factorization.

10040357113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 25.

The spelling of 10040357113 in words is "ten billion, forty million, three hundred fifty-seven thousand, one hundred thirteen".