10040413531 has 2 divisors, whose sum is σ = 10040413532. Its totient is φ = 10040413530.

The previous prime is 10040413507. The next prime is 10040413541. The reversal of 10040413531 is 13531404001.

It is a strong prime.

It is an emirp because it is prime and its reverse (13531404001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10040413531 - 2⁷ = 10040413403 is a prime.

It is a super-2 number, since 2×10040413531² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10040413541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020206765 + 5020206766.

It is an arithmetic number, because the mean of its divisors is an integer number (5020206766).

Almost surely, 2^10040413531 is an apocalyptic number.

10040413531 is a deficient number, since it is larger than the sum of its proper divisors (1).

10040413531 is an equidigital number, since it uses as much as digits as its factorization.

10040413531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 10040413531 its reverse (13531404001), we get a palindrome (23571817532).

The spelling of 10040413531 in words is "ten billion, forty million, four hundred thirteen thousand, five hundred thirty-one".