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10040490433 is a prime number
BaseRepresentation
bin10010101100111010…
…11011100111000001
3221220201221202120001
421112131123213001
5131030331143213
64340150320001
7503545521601
oct112635334701
927821852501
1010040490433
114292660086
121b42659001
13c401c62cc
146b36a2c01
153db70a1dd
hex25675b9c1

10040490433 has 2 divisors, whose sum is σ = 10040490434. Its totient is φ = 10040490432.

The previous prime is 10040490409. The next prime is 10040490437. The reversal of 10040490433 is 33409404001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8551070784 + 1489419649 = 92472^2 + 38593^2 .

It is a cyclic number.

It is not a de Polignac number, because 10040490433 - 225 = 10006936001 is a prime.

It is a super-2 number, since 2×100404904332 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10040490437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020245216 + 5020245217.

It is an arithmetic number, because the mean of its divisors is an integer number (5020245217).

Almost surely, 210040490433 is an apocalyptic number.

It is an amenable number.

10040490433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10040490433 is an equidigital number, since it uses as much as digits as its factorization.

10040490433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 10040490433 its reverse (33409404001), we get a palindrome (43449894434).

The spelling of 10040490433 in words is "ten billion, forty million, four hundred ninety thousand, four hundred thirty-three".