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100411221334331 is a prime number
BaseRepresentation
bin10110110101001011001111…
…001011011101100100111011
3111011112012220122210202010202
4112311023033023131210323
5101130114140130144311
6553320140035032415
730102320445620555
oct2665131713354473
9434465818722122
10100411221334331
1129aa31838010a6
12b31844aa3b70b
1344049784c578b
141ab1d0141c4d5
15b91dd63c7e3b
hex5b52cf2dd93b

100411221334331 has 2 divisors, whose sum is σ = 100411221334332. Its totient is φ = 100411221334330.

The previous prime is 100411221334279. The next prime is 100411221334337. The reversal of 100411221334331 is 133433122114001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100411221334331 is a prime.

It is a super-2 number, since 2×1004112213343312 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 100411221334294 and 100411221334303.

It is not a weakly prime, because it can be changed into another prime (100411221334337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50205610667165 + 50205610667166.

It is an arithmetic number, because the mean of its divisors is an integer number (50205610667166).

Almost surely, 2100411221334331 is an apocalyptic number.

100411221334331 is a deficient number, since it is larger than the sum of its proper divisors (1).

100411221334331 is an equidigital number, since it uses as much as digits as its factorization.

100411221334331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 100411221334331 its reverse (133433122114001), we get a palindrome (233844343448332).

The spelling of 100411221334331 in words is "one hundred trillion, four hundred eleven billion, two hundred twenty-one million, three hundred thirty-four thousand, three hundred thirty-one".