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100412361553 = 714344623079
BaseRepresentation
bin101110110000100001…
…0110000101101010001
3100121011220120110221211
41131201002300231101
53121121031032203
6114043453220121
710153211663530
oct1354102605521
9317156513854
10100412361553
1139648184479
1217563a91641
13961308b76a
144c07b22317
15292a540c6d
hex17610b0b51

100412361553 has 4 divisors (see below), whose sum is σ = 114756984640. Its totient is φ = 86067738468.

The previous prime is 100412361541. The next prime is 100412361613. The reversal of 100412361553 is 355163214001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100412361553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100412361503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7172311533 + ... + 7172311546.

It is an arithmetic number, because the mean of its divisors is an integer number (28689246160).

Almost surely, 2100412361553 is an apocalyptic number.

It is an amenable number.

100412361553 is a deficient number, since it is larger than the sum of its proper divisors (14344623087).

100412361553 is an equidigital number, since it uses as much as digits as its factorization.

100412361553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14344623086.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 100412361553 its reverse (355163214001), we get a palindrome (455575575554).

The spelling of 100412361553 in words is "one hundred billion, four hundred twelve million, three hundred sixty-one thousand, five hundred fifty-three".

Divisors: 1 7 14344623079 100412361553