10041312521 has 2 divisors, whose sum is σ = 10041312522. Its totient is φ = 10041312520.

The previous prime is 10041312493. The next prime is 10041312559. The reversal of 10041312521 is 12521314001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9992801296 + 48511225 = 99964^2 + 6965^2 .

It is a cyclic number.

It is not a de Polignac number, because 10041312521 - 2¹⁸ = 10041050377 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10041312493 and 10041312502.

It is not a weakly prime, because it can be changed into another prime (10041312221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020656260 + 5020656261.

It is an arithmetic number, because the mean of its divisors is an integer number (5020656261).

Almost surely, 2^10041312521 is an apocalyptic number.

It is an amenable number.

10041312521 is a deficient number, since it is larger than the sum of its proper divisors (1).

10041312521 is an equidigital number, since it uses as much as digits as its factorization.

10041312521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 10041312521 its reverse (12521314001), we get a palindrome (22562626522).

The spelling of 10041312521 in words is "ten billion, forty-one million, three hundred twelve thousand, five hundred twenty-one".