10041341130001 has 2 divisors, whose sum is σ = 10041341130002. Its totient is φ = 10041341130000.

The previous prime is 10041341129983. The next prime is 10041341130137. The reversal of 10041341130001 is 10003114314001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8809409844225 + 1231931285776 = 2968065^2 + 1109924^2 .

It is a cyclic number.

It is not a de Polignac number, because 10041341130001 - 2⁷ = 10041341129873 is a prime.

It is not a weakly prime, because it can be changed into another prime (10041341134001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020670565000 + 5020670565001.

It is an arithmetic number, because the mean of its divisors is an integer number (5020670565001).

Almost surely, 2^{10041341130001} is an apocalyptic number.

It is an amenable number.

10041341130001 is a deficient number, since it is larger than the sum of its proper divisors (1).

10041341130001 is an equidigital number, since it uses as much as digits as its factorization.

10041341130001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10041341130001 its reverse (10003114314001), we get a palindrome (20044455444002).

The spelling of 10041341130001 in words is "ten trillion, forty-one billion, three hundred forty-one million, one hundred thirty thousand, one".