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100415113 = 107938459
BaseRepresentation
bin1011111110000…
…11011010001001
320222221121122021
411333003122021
5201201240423
613544124441
72326341301
oct577033211
9228847567
10100415113
11517553a7
1229766721
1317a5a736
14d49c601
158c3795d
hex5fc3689

100415113 has 4 divisors (see below), whose sum is σ = 101353680. Its totient is φ = 99476548.

The previous prime is 100415101. The next prime is 100415137. The reversal of 100415113 is 311514001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100415113 - 225 = 66860681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100415153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 469123 + ... + 469336.

It is an arithmetic number, because the mean of its divisors is an integer number (25338420).

Almost surely, 2100415113 is an apocalyptic number.

It is an amenable number.

100415113 is a deficient number, since it is larger than the sum of its proper divisors (938567).

100415113 is an equidigital number, since it uses as much as digits as its factorization.

100415113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 938566.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 100415113 is about 10020.7341547414. The cubic root of 100415113 is about 464.8002579903.

Adding to 100415113 its reverse (311514001), we get a palindrome (411929114).

The spelling of 100415113 in words is "one hundred million, four hundred fifteen thousand, one hundred thirteen".

Divisors: 1 107 938459 100415113