Base | Representation |
---|---|
bin | 10010101101000111… |
… | …10110111010001001 |
3 | 221220212010100111121 |
4 | 21112203312322021 |
5 | 131031244100423 |
6 | 4340250355241 |
7 | 503566036315 |
oct | 112643667211 |
9 | 27825110447 |
10 | 10042175113 |
11 | 4293600883 |
12 | 1b4312bb21 |
13 | c40666069 |
14 | 6b39c0b45 |
15 | 3db93e45d |
hex | 2568f6e89 |
10042175113 has 2 divisors, whose sum is σ = 10042175114. Its totient is φ = 10042175112.
The previous prime is 10042175093. The next prime is 10042175119. The reversal of 10042175113 is 31157124001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9905822784 + 136352329 = 99528^2 + 11677^2 .
It is an emirp because it is prime and its reverse (31157124001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10042175113 - 221 = 10040077961 is a prime.
It is not a weakly prime, because it can be changed into another prime (10042175119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021087556 + 5021087557.
It is an arithmetic number, because the mean of its divisors is an integer number (5021087557).
Almost surely, 210042175113 is an apocalyptic number.
It is an amenable number.
10042175113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10042175113 is an equidigital number, since it uses as much as digits as its factorization.
10042175113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 25.
Adding to 10042175113 its reverse (31157124001), we get a palindrome (41199299114).
The spelling of 10042175113 in words is "ten billion, forty-two million, one hundred seventy-five thousand, one hundred thirteen".
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