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10042201553 = 43535717717
BaseRepresentation
bin10010101101000111…
…11101010111010001
3221220212011200202212
421112203331113101
5131031300422203
64340251121505
7503566206356
oct112643752721
927825150685
1010042201553
11429361972a
121b43143295
13c406750c7
146b39ca62d
153db9471d8
hex2568fd5d1

10042201553 has 16 divisors (see below), whose sum is σ = 10489317696. Its totient is φ = 9605494080.

The previous prime is 10042201541. The next prime is 10042201583. The reversal of 10042201553 is 35510224001.

It is a cyclic number.

It is not a de Polignac number, because 10042201553 - 212 = 10042197457 is a prime.

It is a super-2 number, since 2×100422015532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10042201583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1297451 + ... + 1305167.

It is an arithmetic number, because the mean of its divisors is an integer number (655582356).

Almost surely, 210042201553 is an apocalyptic number.

It is an amenable number.

10042201553 is a deficient number, since it is larger than the sum of its proper divisors (447116143).

10042201553 is an equidigital number, since it uses as much as digits as its factorization.

10042201553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8384.

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 10042201553 its reverse (35510224001), we get a palindrome (45552425554).

The spelling of 10042201553 in words is "ten billion, forty-two million, two hundred one thousand, five hundred fifty-three".

Divisors: 1 43 53 571 2279 7717 24553 30263 331831 409001 1301309 4406407 17587043 189475501 233539571 10042201553