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1004303545345 = 5835153469631
BaseRepresentation
bin11101001110101010010…
…01111111010000000001
310120000021122022011212101
432213111021333100001
5112423303201422340
62045212022230401
7132362402166322
oct16472511772001
93500248264771
101004303545345
11357a17195241
12142783285401
1373922a59989
1436873c14449
151b1ce49ac9a
hexe9d527f401

1004303545345 has 16 divisors (see below), whose sum is σ = 1219923597312. Its totient is φ = 793607073280.

The previous prime is 1004303545339. The next prime is 1004303545369. The reversal of 1004303545345 is 5435453034001.

1004303545345 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 1004303545345 - 211 = 1004303543297 is a prime.

It is a super-2 number, since 2×10043035453452 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1903680 + ... + 2373310.

It is an arithmetic number, because the mean of its divisors is an integer number (76245224832).

Almost surely, 21004303545345 is an apocalyptic number.

It is an amenable number.

1004303545345 is a deficient number, since it is larger than the sum of its proper divisors (215620051967).

1004303545345 is an equidigital number, since it uses as much as digits as its factorization.

1004303545345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 474872.

The product of its (nonzero) digits is 216000, while the sum is 37.

Adding to 1004303545345 its reverse (5435453034001), we get a palindrome (6439756579346).

The spelling of 1004303545345 in words is "one trillion, four billion, three hundred three million, five hundred forty-five thousand, three hundred forty-five".

Divisors: 1 5 83 415 5153 25765 427699 469631 2138495 2348155 38979373 194896865 2420008543 12100042715 200860709069 1004303545345