Base | Representation |
---|---|
bin | 11101001110101100101… |
… | …00001101000000000001 |
3 | 10120000022222220121002001 |
4 | 32213112110031000001 |
5 | 112423323142002241 |
6 | 2045213555224001 |
7 | 132363026435344 |
oct | 16472624150001 |
9 | 3500288817061 |
10 | 1004323000321 |
11 | 357a27173033 |
12 | 1427898a8001 |
13 | 73926aabcb4 |
14 | 3687663a45b |
15 | 1b1d1040431 |
hex | e9d650d001 |
1004323000321 has 2 divisors, whose sum is σ = 1004323000322. Its totient is φ = 1004323000320.
The previous prime is 1004323000271. The next prime is 1004323000327. The reversal of 1004323000321 is 1230003234001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 652153153600 + 352169846721 = 807560^2 + 593439^2 .
It is a cyclic number.
It is not a de Polignac number, because 1004323000321 - 215 = 1004322967553 is a prime.
It is a super-2 number, since 2×10043230003212 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1004323000327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502161500160 + 502161500161.
It is an arithmetic number, because the mean of its divisors is an integer number (502161500161).
Almost surely, 21004323000321 is an apocalyptic number.
It is an amenable number.
1004323000321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004323000321 is an equidigital number, since it uses as much as digits as its factorization.
1004323000321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 1004323000321 its reverse (1230003234001), we get a palindrome (2234326234322).
The spelling of 1004323000321 in words is "one trillion, four billion, three hundred twenty-three million, three hundred twenty-one", and thus it is an aban number.
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