Base | Representation |
---|---|
bin | 101110110001001011… |
… | …1011011010110101011 |
3 | 100121020110100002110122 |
4 | 1131202113123112223 |
5 | 3121142221300311 |
6 | 114050005033455 |
7 | 10153601433404 |
oct | 1354227332653 |
9 | 317213302418 |
10 | 100434556331 |
11 | 3965976376a |
12 | 1756b3b588b |
13 | 961785cb75 |
14 | 4c0aa5c9ab |
15 | 292c4770db |
hex | 17625db5ab |
100434556331 has 4 divisors (see below), whose sum is σ = 100435489752. Its totient is φ = 100433622912.
The previous prime is 100434556319. The next prime is 100434556399. The reversal of 100434556331 is 133655434001.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 100434556331 - 210 = 100434555307 is a prime.
It is a super-2 number, since 2×1004345563312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100434556291 and 100434556300.
It is not an unprimeable number, because it can be changed into a prime (100434556531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 280565 + ... + 528758.
It is an arithmetic number, because the mean of its divisors is an integer number (25108872438).
Almost surely, 2100434556331 is an apocalyptic number.
100434556331 is a deficient number, since it is larger than the sum of its proper divisors (933421).
100434556331 is an equidigital number, since it uses as much as digits as its factorization.
100434556331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 933420.
The product of its (nonzero) digits is 64800, while the sum is 35.
The spelling of 100434556331 in words is "one hundred billion, four hundred thirty-four million, five hundred fifty-six thousand, three hundred thirty-one".
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