Base | Representation |
---|---|
bin | 10110110101100110011011… |
… | …010001110000101001000010 |
3 | 111011122000021020110221200112 |
4 | 112311212123101300221002 |
5 | 101131103432311403442 |
6 | 553341404555551322 |
7 | 30104403060602153 |
oct | 2665463321605102 |
9 | 434560236427615 |
10 | 100440415341122 |
11 | 2a0045a4a9053a |
12 | b322037a5b542 |
13 | 440764b8b9acc |
14 | 1ab34b07bb92a |
15 | b92a44394082 |
hex | 5b599b470a42 |
100440415341122 has 4 divisors (see below), whose sum is σ = 150660623011686. Its totient is φ = 50220207670560.
The previous prime is 100440415341047. The next prime is 100440415341139. The reversal of 100440415341122 is 221143514044001.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 54356425127761 + 46083990213361 = 7372681^2 + 6788519^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25110103835279 + ... + 25110103835282.
Almost surely, 2100440415341122 is an apocalyptic number.
100440415341122 is a deficient number, since it is larger than the sum of its proper divisors (50220207670564).
100440415341122 is an equidigital number, since it uses as much as digits as its factorization.
100440415341122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50220207670563.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 100440415341122 its reverse (221143514044001), we get a palindrome (321583929385123).
The spelling of 100440415341122 in words is "one hundred trillion, four hundred forty billion, four hundred fifteen million, three hundred forty-one thousand, one hundred twenty-two".
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