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10044331131403 = 58107117285893
BaseRepresentation
bin1001001000101010000011…
…0010100000001000001011
31022120020011201002001200001
42102022200302200020023
52304031242232201103
633210145123023431
72054451613631332
oct222124062401013
938506151061601
1010044331131403
1132228600831a8
1211627aa20ab77
1357b23a60a21a
1426a210a08d19
15126421cad01d
hex922a0ca020b

10044331131403 has 4 divisors (see below), whose sum is σ = 10044348998368. Its totient is φ = 10044313264440.

The previous prime is 10044331131377. The next prime is 10044331131413. The reversal of 10044331131403 is 30413113344001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10044331131403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10044331131413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8061876 + ... + 9224017.

It is an arithmetic number, because the mean of its divisors is an integer number (2511087249592).

Almost surely, 210044331131403 is an apocalyptic number.

10044331131403 is a deficient number, since it is larger than the sum of its proper divisors (17866965).

10044331131403 is an equidigital number, since it uses as much as digits as its factorization.

10044331131403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17866964.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 10044331131403 its reverse (30413113344001), we get a palindrome (40457444475404).

The spelling of 10044331131403 in words is "ten trillion, forty-four billion, three hundred thirty-one million, one hundred thirty-one thousand, four hundred three".

Divisors: 1 581071 17285893 10044331131403