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10051122011257 is a prime number
BaseRepresentation
bin1001001001000011010110…
…0011101001110001111001
31022120212200222022111112201
42102100311203221301321
52304134144213330012
633213231031110201
72055112113310015
oct222206543516171
938525628274481
1010051122011257
1132257253857a8
121163b84512361
1357ba804b4922
1426a69688b545
151266bd06a857
hex924358e9c79

10051122011257 has 2 divisors, whose sum is σ = 10051122011258. Its totient is φ = 10051122011256.

The previous prime is 10051122011243. The next prime is 10051122011311. The reversal of 10051122011257 is 75211022115001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9072168096016 + 978953915241 = 3012004^2 + 989421^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10051122011257 is a prime.

It is not a weakly prime, because it can be changed into another prime (10051122711257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5025561005628 + 5025561005629.

It is an arithmetic number, because the mean of its divisors is an integer number (5025561005629).

Almost surely, 210051122011257 is an apocalyptic number.

It is an amenable number.

10051122011257 is a deficient number, since it is larger than the sum of its proper divisors (1).

10051122011257 is an equidigital number, since it uses as much as digits as its factorization.

10051122011257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1400, while the sum is 28.

Adding to 10051122011257 its reverse (75211022115001), we get a palindrome (85262144126258).

The spelling of 10051122011257 in words is "ten trillion, fifty-one billion, one hundred twenty-two million, eleven thousand, two hundred fifty-seven".