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1005225433 = 7731300421
BaseRepresentation
bin111011111010101…
…000010111011001
32121001111202001121
4323322220113121
54024314203213
6243425245241
733624163252
oct7372502731
92531452047
101005225433
11476472823
12240793821
13130349764
149770bb29
155d3b488d
hex3bea85d9

1005225433 has 4 divisors (see below), whose sum is σ = 1006526628. Its totient is φ = 1003924240.

The previous prime is 1005225407. The next prime is 1005225443. The reversal of 1005225433 is 3345225001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 221057424 + 784168009 = 14868^2 + 28003^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1005225433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1005225398 and 1005225407.

It is not an unprimeable number, because it can be changed into a prime (1005225443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 649438 + ... + 650983.

It is an arithmetic number, because the mean of its divisors is an integer number (251631657).

Almost surely, 21005225433 is an apocalyptic number.

It is an amenable number.

1005225433 is a deficient number, since it is larger than the sum of its proper divisors (1301195).

1005225433 is an equidigital number, since it uses as much as digits as its factorization.

1005225433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1301194.

The product of its (nonzero) digits is 3600, while the sum is 25.

The square root of 1005225433 is about 31705.2902998853. The cubic root of 1005225433 is about 1001.7387858714.

The spelling of 1005225433 in words is "one billion, five million, two hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 773 1300421 1005225433