Search a number
-
+
100531376081 is a prime number
BaseRepresentation
bin101110110100000100…
…0110000111111010001
3100121111012112001012022
41131220020300333101
53121342013013311
6114103344141225
710156155411623
oct1355010607721
9317435461168
10100531376081
11396a9382894
1217597907815
13963192bc66
144c19862c13
152935bee5db
hex1768230fd1

100531376081 has 2 divisors, whose sum is σ = 100531376082. Its totient is φ = 100531376080.

The previous prime is 100531376051. The next prime is 100531376089. The reversal of 100531376081 is 180673135001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82897926400 + 17633449681 = 287920^2 + 132791^2 .

It is an emirp because it is prime and its reverse (180673135001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100531376081 is a prime.

It is a super-2 number, since 2×1005313760812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (100531376089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50265688040 + 50265688041.

It is an arithmetic number, because the mean of its divisors is an integer number (50265688041).

Almost surely, 2100531376081 is an apocalyptic number.

It is an amenable number.

100531376081 is a deficient number, since it is larger than the sum of its proper divisors (1).

100531376081 is an equidigital number, since it uses as much as digits as its factorization.

100531376081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 35.

The spelling of 100531376081 in words is "one hundred billion, five hundred thirty-one million, three hundred seventy-six thousand, eighty-one".