10053147405641 has 2 divisors, whose sum is σ = 10053147405642. Its totient is φ = 10053147405640.

The previous prime is 10053147405577. The next prime is 10053147405667. The reversal of 10053147405641 is 14650474135001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7477058205241 + 2576089200400 = 2734421^2 + 1605020^2 .

It is an emirp because it is prime and its reverse (14650474135001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10053147405641 - 2⁶ = 10053147405577 is a prime.

It is a super-3 number, since 3×10053147405641³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10053140405641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5026573702820 + 5026573702821.

It is an arithmetic number, because the mean of its divisors is an integer number (5026573702821).

Almost surely, 2^{10053147405641} is an apocalyptic number.

It is an amenable number.

10053147405641 is a deficient number, since it is larger than the sum of its proper divisors (1).

10053147405641 is an equidigital number, since it uses as much as digits as its factorization.

10053147405641 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 201600, while the sum is 41.

The spelling of 10053147405641 in words is "ten trillion, fifty-three billion, one hundred forty-seven million, four hundred five thousand, six hundred forty-one".