Search a number
-
+
1005500000003 = 2732813679363
BaseRepresentation
bin11101010000111000111…
…10000110011100000011
310120010101000122101002212
432220130132012130003
5112433231000000003
62045530442332335
7132434140660322
oct16503436063403
93503330571085
101005500000003
1135848059a344
12142a57aba0ab
1373a838ac505
1436948aa00b9
151b24e535dd8
hexea1c786703

1005500000003 has 4 divisors (see below), whose sum is σ = 1005503952648. Its totient is φ = 1005496047360.

The previous prime is 1005499999949. The next prime is 1005500000009. The reversal of 1005500000003 is 3000000055001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1005500000003 - 238 = 730622093059 is a prime.

It is a super-2 number, since 2×10055000000032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1005500000009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1566401 + ... + 2112962.

It is an arithmetic number, because the mean of its divisors is an integer number (251375988162).

Almost surely, 21005500000003 is an apocalyptic number.

1005500000003 is a deficient number, since it is larger than the sum of its proper divisors (3952645).

1005500000003 is an equidigital number, since it uses as much as digits as its factorization.

1005500000003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3952644.

The product of its (nonzero) digits is 75, while the sum is 14.

Adding to 1005500000003 its reverse (3000000055001), we get a palindrome (4005500055004).

The spelling of 1005500000003 in words is "one trillion, five billion, five hundred million, three", and thus it is an aban number.

Divisors: 1 273281 3679363 1005500000003