Base | Representation |
---|---|
bin | 10110110111011011100110… |
… | …001011110101010001111010 |
3 | 111012002001000012200020001102 |
4 | 112313123212023311101322 |
5 | 101140134112342130132 |
6 | 553515253025451402 |
7 | 30116445555632141 |
oct | 2667334613652172 |
9 | 435061005606042 |
10 | 100566226130042 |
11 | 2a052995992352 |
12 | b3424a97a0b62 |
13 | 441647b8c25ca |
14 | 1ab960775c758 |
15 | b95e59559c62 |
hex | 5b76e62f547a |
100566226130042 has 4 divisors (see below), whose sum is σ = 150849339195066. Its totient is φ = 50283113065020.
The previous prime is 100566226130033. The next prime is 100566226130099. The reversal of 100566226130042 is 240031622665001.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 97650939658801 + 2915286471241 = 9881849^2 + 1707421^2 .
It is a super-2 number, since 2×1005662261300422 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100566226129978 and 100566226130005.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25141556532509 + ... + 25141556532512.
Almost surely, 2100566226130042 is an apocalyptic number.
100566226130042 is a deficient number, since it is larger than the sum of its proper divisors (50283113065024).
100566226130042 is an equidigital number, since it uses as much as digits as its factorization.
100566226130042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50283113065023.
The product of its (nonzero) digits is 103680, while the sum is 38.
Adding to 100566226130042 its reverse (240031622665001), we get a palindrome (340597848795043).
The spelling of 100566226130042 in words is "one hundred trillion, five hundred sixty-six billion, two hundred twenty-six million, one hundred thirty thousand, forty-two".
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