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1006022124313 = 1557236460331
BaseRepresentation
bin11101010001110111001…
…01110110001100011001
310120011201102010001000021
432220323211312030121
5112440313130434223
62050054333310441
7132453110651533
oct16507345661431
93504642101007
101006022124313
11358719298038
12142b82935421
1373b37b0c8cb
1436998174853
151b2802be65d
hexea3b976319

1006022124313 has 4 divisors (see below), whose sum is σ = 1006028740368. Its totient is φ = 1006015508260.

The previous prime is 1006022124307. The next prime is 1006022124337. The reversal of 1006022124313 is 3134212206001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1006022124313 - 25 = 1006022124281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1006022124113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3074443 + ... + 3385888.

It is an arithmetic number, because the mean of its divisors is an integer number (251507185092).

Almost surely, 21006022124313 is an apocalyptic number.

It is an amenable number.

1006022124313 is a deficient number, since it is larger than the sum of its proper divisors (6616055).

1006022124313 is an equidigital number, since it uses as much as digits as its factorization.

1006022124313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6616054.

The product of its (nonzero) digits is 1728, while the sum is 25.

The spelling of 1006022124313 in words is "one trillion, six billion, twenty-two million, one hundred twenty-four thousand, three hundred thirteen".

Divisors: 1 155723 6460331 1006022124313