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1006331351281 is a prime number
BaseRepresentation
bin11101010010011100000…
…01011101000011110001
310120012111221222101122221
432221032001131003301
5112441431311220111
62050145141201041
7132463554231064
oct16511601350361
93505457871587
101006331351281
113588678a3913
1214304a400181
1373b86bbb449
14369c726a8db
151b29c502371
hexea4e05d0f1

1006331351281 has 2 divisors, whose sum is σ = 1006331351282. Its totient is φ = 1006331351280.

The previous prime is 1006331351203. The next prime is 1006331351327. The reversal of 1006331351281 is 1821531336001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 940979541681 + 65351809600 = 970041^2 + 255640^2 .

It is a cyclic number.

It is not a de Polignac number, because 1006331351281 - 227 = 1006197133553 is a prime.

It is a super-2 number, since 2×10063313512812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1006331351881) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 503165675640 + 503165675641.

It is an arithmetic number, because the mean of its divisors is an integer number (503165675641).

Almost surely, 21006331351281 is an apocalyptic number.

It is an amenable number.

1006331351281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1006331351281 is an equidigital number, since it uses as much as digits as its factorization.

1006331351281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 34.

Adding to 1006331351281 its reverse (1821531336001), we get a palindrome (2827862687282).

The spelling of 1006331351281 in words is "one trillion, six billion, three hundred thirty-one million, three hundred fifty-one thousand, two hundred eighty-one".