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1006834756273 is a prime number
BaseRepresentation
bin11101010011011000000…
…01110010101010110001
310120020211001020000111021
432221230001302222301
5112443444144200043
62050311123015441
7132512206136113
oct16515401625261
93506731200437
101006834756273
11358aa5a764a5
1214316ab0a581
1373c37296318
1436a3406b3b3
151b2cb7de3ed
hexea6c072ab1

1006834756273 has 2 divisors, whose sum is σ = 1006834756274. Its totient is φ = 1006834756272.

The previous prime is 1006834756261. The next prime is 1006834756289. The reversal of 1006834756273 is 3726574386001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 839380295329 + 167454460944 = 916177^2 + 409212^2 .

It is a cyclic number.

It is not a de Polignac number, because 1006834756273 - 25 = 1006834756241 is a prime.

It is a super-2 number, since 2×10068347562732 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1006834756273.

It is not a weakly prime, because it can be changed into another prime (1006834756243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 503417378136 + 503417378137.

It is an arithmetic number, because the mean of its divisors is an integer number (503417378137).

Almost surely, 21006834756273 is an apocalyptic number.

It is an amenable number.

1006834756273 is a deficient number, since it is larger than the sum of its proper divisors (1).

1006834756273 is an equidigital number, since it uses as much as digits as its factorization.

1006834756273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5080320, while the sum is 52.

The spelling of 1006834756273 in words is "one trillion, six billion, eight hundred thirty-four million, seven hundred fifty-six thousand, two hundred seventy-three".