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100763217433 is a prime number
BaseRepresentation
bin101110111010111110…
…1001010111000011001
3100122002100202210202001
41131311331022320121
53122330340424213
6114142345241001
710165002134134
oct1356575127031
9318070683661
10100763217433
113980823370a
1217641493161
13966a9843a8
144c3c57321b
15294b2481dd
hex1775f4ae19

100763217433 has 2 divisors, whose sum is σ = 100763217434. Its totient is φ = 100763217432.

The previous prime is 100763217371. The next prime is 100763217461. The reversal of 100763217433 is 334712367001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81197642304 + 19565575129 = 284952^2 + 139877^2 .

It is an emirp because it is prime and its reverse (334712367001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100763217433 - 213 = 100763209241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100763217392 and 100763217401.

It is not a weakly prime, because it can be changed into another prime (100763217493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50381608716 + 50381608717.

It is an arithmetic number, because the mean of its divisors is an integer number (50381608717).

Almost surely, 2100763217433 is an apocalyptic number.

It is an amenable number.

100763217433 is a deficient number, since it is larger than the sum of its proper divisors (1).

100763217433 is an equidigital number, since it uses as much as digits as its factorization.

100763217433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63504, while the sum is 37.

The spelling of 100763217433 in words is "one hundred billion, seven hundred sixty-three million, two hundred seventeen thousand, four hundred thirty-three".