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100916749753 is a prime number
BaseRepresentation
bin101110111111100011…
…0110110010110111001
3100122111001200001111021
41131333012312112321
53123134141443003
6114205512102441
710201545135211
oct1357706662671
9318431601437
10100916749753
1139886968826
1217684994a21
13969371c011
144c54adb241
1529599742bd
hex177f1b65b9

100916749753 has 2 divisors, whose sum is σ = 100916749754. Its totient is φ = 100916749752.

The previous prime is 100916749741. The next prime is 100916749799. The reversal of 100916749753 is 357947619001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65590795449 + 35325954304 = 256107^2 + 187952^2 .

It is a cyclic number.

It is not a de Polignac number, because 100916749753 - 213 = 100916741561 is a prime.

It is a super-2 number, since 2×1009167497532 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 100916749753.

It is not a weakly prime, because it can be changed into another prime (100916749253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50458374876 + 50458374877.

It is an arithmetic number, because the mean of its divisors is an integer number (50458374877).

Almost surely, 2100916749753 is an apocalyptic number.

It is an amenable number.

100916749753 is a deficient number, since it is larger than the sum of its proper divisors (1).

100916749753 is an equidigital number, since it uses as much as digits as its factorization.

100916749753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1428840, while the sum is 52.

The spelling of 100916749753 in words is "one hundred billion, nine hundred sixteen million, seven hundred forty-nine thousand, seven hundred fifty-three".