Base | Representation |
---|---|
bin | 10010110100000000… |
… | …11100010100010001 |
3 | 222001212221011100201 |
4 | 21122000130110101 |
5 | 131141100000032 |
6 | 4350114015201 |
7 | 505200404122 |
oct | 113200342421 |
9 | 28055834321 |
10 | 10100000017 |
11 | 4313206558 |
12 | 1b5a577501 |
13 | c4c630c93 |
14 | 6bb554049 |
15 | 3e1a628e7 |
hex | 25a01c511 |
10100000017 has 2 divisors, whose sum is σ = 10100000018. Its totient is φ = 10100000016.
The previous prime is 10100000011. The next prime is 10100000021. The reversal of 10100000017 is 71000000101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8085426561 + 2014573456 = 89919^2 + 44884^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10100000017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10099999949 and 10100000012.
It is not a weakly prime, because it can be changed into another prime (10100000011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050000008 + 5050000009.
It is an arithmetic number, because the mean of its divisors is an integer number (5050000009).
Almost surely, 210100000017 is an apocalyptic number.
It is an amenable number.
10100000017 is a deficient number, since it is larger than the sum of its proper divisors (1).
10100000017 is an equidigital number, since it uses as much as digits as its factorization.
10100000017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7, while the sum is 10.
Adding to 10100000017 its reverse (71000000101), we get a palindrome (81100000118).
The spelling of 10100000017 in words is "ten billion, one hundred million, seventeen", and thus it is an aban number.
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