101001312019 has 2 divisors, whose sum is σ = 101001312020. Its totient is φ = 101001312018.

The previous prime is 101001311981. The next prime is 101001312029. The reversal of 101001312019 is 910213100101.

It is a strong prime.

It is an emirp because it is prime and its reverse (910213100101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101001312019 - 2¹¹ = 101001309971 is a prime.

It is a super-2 number, since 2×101001312019² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101001311987 and 101001312005.

It is not a weakly prime, because it can be changed into another prime (101001312029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500656009 + 50500656010.

It is an arithmetic number, because the mean of its divisors is an integer number (50500656010).

Almost surely, 2^101001312019 is an apocalyptic number.

101001312019 is a deficient number, since it is larger than the sum of its proper divisors (1).

101001312019 is an equidigital number, since it uses as much as digits as its factorization.

101001312019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 19.

The spelling of 101001312019 in words is "one hundred one billion, one million, three hundred twelve thousand, nineteen".