Base | Representation |
---|---|
bin | 101111000010000110… |
… | …1101000000001100011 |
3 | 100122201000212011011221 |
4 | 1132010031220001203 |
5 | 3123323104142011 |
6 | 114222212115511 |
7 | 10203635223565 |
oct | 1360415500143 |
9 | 318630764157 |
10 | 101002412131 |
11 | 39920257185 |
12 | 176a9605b97 |
13 | 96a83b280a |
14 | 4c62239335 |
15 | 2962245971 |
hex | 1784368063 |
101002412131 has 2 divisors, whose sum is σ = 101002412132. Its totient is φ = 101002412130.
The previous prime is 101002412081. The next prime is 101002412143. The reversal of 101002412131 is 131214200101.
It is a strong prime.
It is an emirp because it is prime and its reverse (131214200101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101002412131 - 217 = 101002281059 is a prime.
It is a super-2 number, since 2×1010024121312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101003412131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50501206065 + 50501206066.
It is an arithmetic number, because the mean of its divisors is an integer number (50501206066).
Almost surely, 2101002412131 is an apocalyptic number.
101002412131 is a deficient number, since it is larger than the sum of its proper divisors (1).
101002412131 is an equidigital number, since it uses as much as digits as its factorization.
101002412131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 101002412131 its reverse (131214200101), we get a palindrome (232216612232).
The spelling of 101002412131 in words is "one hundred one billion, two million, four hundred twelve thousand, one hundred thirty-one".
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