10100404131 has 8 divisors (see below), whose sum is σ = 13467729600. Its totient is φ = 6733340712.

The previous prime is 10100404121. The next prime is 10100404141. The reversal of 10100404131 is 13140400101.

It is an interprime number because it is at equal distance from previous prime (10100404121) and next prime (10100404141).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10100404131 - 2⁵ = 10100404099 is a prime.

It is a super-2 number, since 2×10100404131² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10100404131.

It is not an unprimeable number, because it can be changed into a prime (10100404121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57336 + ... + 153258.

It is an arithmetic number, because the mean of its divisors is an integer number (1683466200).

Almost surely, 2^10100404131 is an apocalyptic number.

10100404131 is a deficient number, since it is larger than the sum of its proper divisors (3367325469).

10100404131 is an equidigital number, since it uses as much as digits as its factorization.

10100404131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131025.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 10100404131 its reverse (13140400101), we get a palindrome (23240804232).

The spelling of 10100404131 in words is "ten billion, one hundred million, four hundred four thousand, one hundred thirty-one".