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10100540314147 is a prime number
BaseRepresentation
bin1001001011111011011100…
…0111100001001000100011
31022202121021000120101202011
42102332313013201020203
52310441401310023042
633252042452533351
72061511543043563
oct222766707411043
938677230511664
1010100540314147
113244684761138
121171676621257
1358362789687a
1426cc23c3ada3
15127b1180aa17
hex92fb71e1223

10100540314147 has 2 divisors, whose sum is σ = 10100540314148. Its totient is φ = 10100540314146.

The previous prime is 10100540314099. The next prime is 10100540314159. The reversal of 10100540314147 is 74141304500101.

10100540314147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10100540314147 - 27 = 10100540314019 is a prime.

It is not a weakly prime, because it can be changed into another prime (10100540314547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050270157073 + 5050270157074.

It is an arithmetic number, because the mean of its divisors is an integer number (5050270157074).

Almost surely, 210100540314147 is an apocalyptic number.

10100540314147 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100540314147 is an equidigital number, since it uses as much as digits as its factorization.

10100540314147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 10100540314147 its reverse (74141304500101), we get a palindrome (84241844814248).

The spelling of 10100540314147 in words is "ten trillion, one hundred billion, five hundred forty million, three hundred fourteen thousand, one hundred forty-seven".