10100843343361 has 2 divisors, whose sum is σ = 10100843343362. Its totient is φ = 10100843343360.

The previous prime is 10100843343329. The next prime is 10100843343377. The reversal of 10100843343361 is 16334334800101.

10100843343361 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6413556250000 + 3687287093361 = 2532500^2 + 1920231^2 .

It is a cyclic number.

It is not a de Polignac number, because 10100843343361 - 2⁵ = 10100843343329 is a prime.

It is a super-3 number, since 3×10100843343361³ (a number of 40 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10100843343361.

It is not a weakly prime, because it can be changed into another prime (10100843343761) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050421671680 + 5050421671681.

It is an arithmetic number, because the mean of its divisors is an integer number (5050421671681).

Almost surely, 2^{10100843343361} is an apocalyptic number.

It is an amenable number.

10100843343361 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100843343361 is an equidigital number, since it uses as much as digits as its factorization.

10100843343361 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 37.

The spelling of 10100843343361 in words is "ten trillion, one hundred billion, eight hundred forty-three million, three hundred forty-three thousand, three hundred sixty-one".