Base | Representation |
---|---|
bin | 10010110100011011… |
… | …00000010110110001 |
3 | 222002010101010202221 |
4 | 21122031200112301 |
5 | 131142434040213 |
6 | 4350315241041 |
7 | 505241455624 |
oct | 113215402661 |
9 | 28063333687 |
10 | 10103424433 |
11 | 4315135353 |
12 | 1b5b749181 |
13 | c5025c86b |
14 | 6bbba5dbb |
15 | 3e1edc38d |
hex | 25a3605b1 |
10103424433 has 4 divisors (see below), whose sum is σ = 10103639920. Its totient is φ = 10103208948.
The previous prime is 10103424431. The next prime is 10103424451. The reversal of 10103424433 is 33442430101.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10103424433 - 21 = 10103424431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10103424398 and 10103424407.
It is not an unprimeable number, because it can be changed into a prime (10103424431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4323 + ... + 142216.
It is an arithmetic number, because the mean of its divisors is an integer number (2525909980).
Almost surely, 210103424433 is an apocalyptic number.
It is an amenable number.
10103424433 is a deficient number, since it is larger than the sum of its proper divisors (215487).
10103424433 is an equidigital number, since it uses as much as digits as its factorization.
10103424433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 215486.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 10103424433 its reverse (33442430101), we get a palindrome (43545854534).
The spelling of 10103424433 in words is "ten billion, one hundred three million, four hundred twenty-four thousand, four hundred thirty-three".
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