10103434113 has 4 divisors (see below), whose sum is σ = 13471245488. Its totient is φ = 6735622740.

The previous prime is 10103434097. The next prime is 10103434127. The reversal of 10103434113 is 31143430101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10103434113 - 2⁴ = 10103434097 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10103434113.

It is not an unprimeable number, because it can be changed into a prime (10103439113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1683905683 + ... + 1683905688.

It is an arithmetic number, because the mean of its divisors is an integer number (3367811372).

Almost surely, 2^10103434113 is an apocalyptic number.

It is an amenable number.

10103434113 is a deficient number, since it is larger than the sum of its proper divisors (3367811375).

10103434113 is an equidigital number, since it uses as much as digits as its factorization.

10103434113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3367811374.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10103434113 its reverse (31143430101), we get a palindrome (41246864214).

The spelling of 10103434113 in words is "ten billion, one hundred three million, four hundred thirty-four thousand, one hundred thirteen".