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10110009748057 is a prime number
BaseRepresentation
bin1001001100011110101110…
…0010100010101001011001
31022210111200221222111000121
42103013223202202221121
52311120244443414212
633300250243433241
72062265315644612
oct223075342425131
938714627874017
1010110009748057
1132486a3a31a7a
121173479985821
135844a66893bb
1426d48172cc09
15127eb7d13d07
hex931eb8a2a59

10110009748057 has 2 divisors, whose sum is σ = 10110009748058. Its totient is φ = 10110009748056.

The previous prime is 10110009748031. The next prime is 10110009748061. The reversal of 10110009748057 is 75084790001101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9508274435401 + 601735312656 = 3083549^2 + 775716^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110009748057 - 227 = 10109875530329 is a prime.

It is a super-3 number, since 3×101100097480573 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10110003748057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055004874028 + 5055004874029.

It is an arithmetic number, because the mean of its divisors is an integer number (5055004874029).

Almost surely, 210110009748057 is an apocalyptic number.

It is an amenable number.

10110009748057 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110009748057 is an equidigital number, since it uses as much as digits as its factorization.

10110009748057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 70560, while the sum is 43.

Adding to 10110009748057 its reverse (75084790001101), we get a palindrome (85194799749158).

The spelling of 10110009748057 in words is "ten trillion, one hundred ten billion, nine million, seven hundred forty-eight thousand, fifty-seven".