101100106055033 has 2 divisors, whose sum is σ = 101100106055034. Its totient is φ = 101100106055032.

The previous prime is 101100106055029. The next prime is 101100106055077. The reversal of 101100106055033 is 330550601001101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88514377771264 + 12585728283769 = 9408208^2 + 3547637^2 .

It is a cyclic number.

It is not a de Polignac number, because 101100106055033 - 2² = 101100106055029 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101100106054993 and 101100106055011.

It is not a weakly prime, because it can be changed into another prime (101100106055093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550053027516 + 50550053027517.

It is an arithmetic number, because the mean of its divisors is an integer number (50550053027517).

Almost surely, 2^{101100106055033} is an apocalyptic number.

It is an amenable number.

101100106055033 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100106055033 is an equidigital number, since it uses as much as digits as its factorization.

101100106055033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350, while the sum is 26.

Adding to 101100106055033 its reverse (330550601001101), we get a palindrome (431650707056134).

The spelling of 101100106055033 in words is "one hundred one trillion, one hundred billion, one hundred six million, fifty-five thousand, thirty-three".