1011004439993 has 4 divisors (see below), whose sum is σ = 1011007905168. Its totient is φ = 1011000974820.

The previous prime is 1011004439971. The next prime is 1011004439999. The reversal of 1011004439993 is 3999344001101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1011004439993 - 2⁸ = 1011004439737 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1011004439999) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1250171 + ... + 1893392.

It is an arithmetic number, because the mean of its divisors is an integer number (252751976292).

Almost surely, 2^{1011004439993} is an apocalyptic number.

It is an amenable number.

1011004439993 is a deficient number, since it is larger than the sum of its proper divisors (3465175).

1011004439993 is an equidigital number, since it uses as much as digits as its factorization.

1011004439993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3465174.

The product of its (nonzero) digits is 104976, while the sum is 44.

The spelling of 1011004439993 in words is "one trillion, eleven billion, four million, four hundred thirty-nine thousand, nine hundred ninety-three".