Base | Representation |
---|---|
bin | 11101011011001001000… |
… | …11110111111000100001 |
3 | 10120122120122012220101111 |
4 | 32231210203313320201 |
5 | 113031014114040342 |
6 | 2052240553503321 |
7 | 133020426643531 |
oct | 16554443677041 |
9 | 3518518186344 |
10 | 1011004440097 |
11 | 35a845716693 |
12 | 143b33411b41 |
13 | 744500b9162 |
14 | 36d0bb514c1 |
15 | 1b4728d1217 |
hex | eb648f7e21 |
1011004440097 has 2 divisors, whose sum is σ = 1011004440098. Its totient is φ = 1011004440096.
The previous prime is 1011004440023. The next prime is 1011004440107. The reversal of 1011004440097 is 7900444001101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 894280400896 + 116724039201 = 945664^2 + 341649^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1011004440097 is a prime.
It is a super-2 number, since 2×10110044400972 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1041004440097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505502220048 + 505502220049.
It is an arithmetic number, because the mean of its divisors is an integer number (505502220049).
Almost surely, 21011004440097 is an apocalyptic number.
It is an amenable number.
1011004440097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011004440097 is an equidigital number, since it uses as much as digits as its factorization.
1011004440097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 31.
Adding to 1011004440097 its reverse (7900444001101), we get a palindrome (8911448441198).
The spelling of 1011004440097 in words is "one trillion, eleven billion, four million, four hundred forty thousand, ninety-seven".
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