Base | Representation |
---|---|
bin | 10110111111001101001011… |
… | …011100111011101000001011 |
3 | 111020222010001202012120122111 |
4 | 112333031023130323220023 |
5 | 101222412311232243021 |
6 | 555004532355403151 |
7 | 30203161443602422 |
oct | 2677151334735013 |
9 | 436863052176574 |
10 | 101100501056011 |
11 | 2a239533185a46 |
12 | b409b552b34b7 |
13 | 4454975985b62 |
14 | 1ad740ca682b9 |
15 | ba4cc92468e1 |
hex | 5bf34b73ba0b |
101100501056011 has 16 divisors (see below), whose sum is σ = 106750043281728. Its totient is φ = 95558558515200.
The previous prime is 101100501055997. The next prime is 101100501056033. The reversal of 101100501056011 is 110650105001101.
It is a cyclic number.
It is not a de Polignac number, because 101100501056011 - 25 = 101100501055979 is a prime.
It is a super-3 number, since 3×1011005010560113 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (101100501096011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33918000 + ... + 36778141.
It is an arithmetic number, because the mean of its divisors is an integer number (6671877705108).
Almost surely, 2101100501056011 is an apocalyptic number.
101100501056011 is a deficient number, since it is larger than the sum of its proper divisors (5649542225717).
101100501056011 is an equidigital number, since it uses as much as digits as its factorization.
101100501056011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70696902.
The product of its (nonzero) digits is 150, while the sum is 22.
Adding to 101100501056011 its reverse (110650105001101), we get a palindrome (211750606057112).
The spelling of 101100501056011 in words is "one hundred one trillion, one hundred billion, five hundred one million, fifty-six thousand, eleven".
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