Base | Representation |
---|---|
bin | 10110111111001101101111… |
… | …001010000110100110000011 |
3 | 111020222011121111102011110211 |
4 | 112333031233022012212003 |
5 | 101222420023111144341 |
6 | 555005112035134551 |
7 | 30203212336440316 |
oct | 2677155712064603 |
9 | 436864544364424 |
10 | 101101100099971 |
11 | 2a2398103405a4 |
12 | b40a0a1a44457 |
13 | 4454a3cb0853a |
14 | 1ad746844297d |
15 | ba4d11b26181 |
hex | 5bf36f286983 |
101101100099971 has 2 divisors, whose sum is σ = 101101100099972. Its totient is φ = 101101100099970.
The previous prime is 101101100099933. The next prime is 101101100100041. The reversal of 101101100099971 is 179990001101101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101101100099971 - 211 = 101101100097923 is a prime.
It is a super-2 number, since 2×1011011000999712 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101101100099771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550550049985 + 50550550049986.
It is an arithmetic number, because the mean of its divisors is an integer number (50550550049986).
Almost surely, 2101101100099971 is an apocalyptic number.
101101100099971 is a deficient number, since it is larger than the sum of its proper divisors (1).
101101100099971 is an equidigital number, since it uses as much as digits as its factorization.
101101100099971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5103, while the sum is 40.
The spelling of 101101100099971 in words is "one hundred one trillion, one hundred one billion, one hundred million, ninety-nine thousand, nine hundred seventy-one".
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